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Q: How many numbers are there from 1 to 101 that are multiples of 3 and are even numbers?

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16

8

101

There are 16 multiples of 6 in that range.

There are 33 multiples of 3 in the range. as first and last are both odd there must be 17 odd and 16 even. Also note that such numbers must be multiples of 6 and 16 x 6 = 96

101

101

The numbers that are between 55 and 101 that are also multiples of 3, 10 and 15 are: 60, 75 and 90.

The multiples of a number are normally obtained by multiplying the number by each of the natural numbers. The multiples of 101 would therefore be 202, 303, 404, etc. (If you were actually looking for the divisors of 101, 101 is a prime number, so is only divisible by 1 and itself.)

101

Just one: 84.

80

80.

The average of the first n even numbers is n+1, so 101.The average of the first n even numbers is n+1, so 101.The average of the first n even numbers is n+1, so 101.The average of the first n even numbers is n+1, so 101.

Just 84

just 80

Just 84.

Just 80

Any multiple of 10 is also a multiple of 5, so all you need to do is find the multiples of 10. Those are the numbers that end with zero.

The first five multiples of 101: 101, 202, 303, 404, 505

90 is the only one.

Just 90

Lots of prime numbers have zeros in them. 101, 103, 107 and 109 are all prime numbers. Prime numbers can't end in zero. Numbers that end in zero are multiples of ten and have too many factors to be prime numbers.

Four. They are 101, 103, 107, and 109.Note:All prime numbers are odd, except '2'. All other even numbersare multiples of 2, so none of them can be primes.

There are 179 multiples of 5 between 101 and 999. 101 ÷ 5 = 201/5 → first multiple of 5 ≥ 101 is 21 x 5 999 ÷ 5 = 1994/5 → last multiple of 5 ≤ 999 is 199 x 5 → number of multiples of 5 between 101 and 999 is 199 - 21 + 1 = 179.